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Originally Posted by Tonkatoy77
I have always been taught that engine load is based on air flow vs. fuel used.
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Air Flow vs fuel used (in mass) is simply the air fuel ratio. It varies from 14.7 to 1 to 12 to 1. (In a gas engine.) It has nothing to do with load. In a diesel, this is not typically even applicable but the range is much wider and much more complex.
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I have never used the equation you are using to determine engine load. And neither does combustion engine manufacturers.
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Really?
It is one of the most common of all formulae used in physics and especially in reciprocating engines of all kinds. It is this formula: 33,000
ft-lbf/min adjusted for rotating motion. Guy named James Watt came up with it...
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Based on what you are saying if I was coming down a 7% grade with my pickup and TT at 2500 RPM's my engine would still be under load. The way I was taught there would be no load because there would be no fuel.
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??? In either a diesel or gas engine, there is no HP being developed by the engine when going down a hill. Both engines shut the fuel off when decelerating. Look at the formula again. Torque would = 0 going down a hill. (actually it would be minus....)
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You asked what I am calling load. It would be energy used.
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Then the energy used would be in HP, or BTU, or KWH. "Load" could loosely be used when discussing torque, (as in foot lbs. of force)