Originally Posted by OldCoot
BTW, how can 300# not be consistent and what is pitch along the axis?
Because along a 200" length (perfectly level) the weight distribution is not the same along the entire length. You may have 5#'s per inch for a certain length while further down the line that may increase to 20#'s. So if you place a determined weight 60"'s from one end, either in the former or the later length the lever weight may be significantly different and impact the weight differential on one end or the other.
The pitch or degree of incline/decline will be affected by gravity. So when you are trying to calculate weight increase at point A, you would also have to account for degree and gravimetric shift on that specific point.
IOW, there is no simple calculation that can be done to determine a specific weights impact on your pin weight. You might get close enough for hand grenades or horseshoes, but if you're down to the wire on you max gross limits, find yourself an MIT grad or just weight it up on the scales.
OC's response was spot on for what you asked, but may not necessarily translate to real world applications for what you are actually trying to accomplish.