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Old 10-22-2010, 11:08 AM   #11
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I think that there is a risk of it getting too complicated versus all of the features contemplated. I don't want to have to pull out an "owners manual" every time I use the trailer to operate the light! Good luck to you though. There would be a real market for a 921 replacement of high quality. I'll be watching for it!!
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Old 10-22-2010, 11:43 AM   #12
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Instead of a complex series of on/off to change the behaviour, maybe just have a DIP switch on the LED panel itself to select the desired behaviour. Normal/Low/Fade Off.
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Old 10-23-2010, 08:41 AM   #13
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the capacitor or a small recharable battery should work. i wouldn't worry abt the feedback. once the switch is off, there isn't any place for it to go. don't need the blocking diodes. how are u accounting for the light. in the finished product, if the bulb is and its' entire circuit is contained within the light socket, how do u keep the reflected light from interfearing with ur sensor? one idea would be to put the sensor in a wall mounted light switch. that would also give u a source of power to keep a processor powered.
once the voltage drops to 11v, is ur circuit going to continue to draw current or are u going to switch it out until the power is removed and restored?
if u used two stages, the power could be applied to one set of led's. the other set could be switched in with a photocell and a switching transistor. time delay, ur back to using a power source...a 9v rechargable bat and a ne555? put it on the second set of led's. or u could size a capacitor that would give u enough energy for the time required (size might restrict u here).
the more u add, the more the cost, the more chances for problems. KISS...
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Old 10-23-2010, 10:40 AM   #14
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jimh,
There is no light sensor. The product is just a bulb replacement.
There is a small capacitor that runs the microcontroller for about 2 seconds so it can remember what mode it is in. If the switch is off for more than 2 seconds it starts in normal mode again.

The circuit is not very complecated. A 3.3V regulator, a couple caps, the microcontroller, 9 LEDs, three transistors and some resistors.

The GP0 input on the microcontroller senses when the switch is turned off.

The C1 capacitor keeps the microcontroller running for a couple seconds even when the power is turned off.

The transistors and 20 ohm resistors create a constant current of 125mA through the LEDs regardless of the voltage.

Each string of LEDs draws 125mA plus a some for the microcontroller so total of about 400mA for full power.

Any questions, please ask.

Bean
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Old 10-24-2010, 12:49 AM   #15
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as drawn, i don't see the reason for the microprocessor. are all 3 2N2222 switching transistors tied to the same pin on the microprocessor or is this just simplified? looks like this could be accomplished with just a switch.
does the processor have an internal clock or do u have to supply one?
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Old 10-31-2010, 09:01 PM   #16
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I've had some people ask for a high quality, high effecency LED light. So I've decied to re-design the circuit to make it as highly effecient as I can.

I'll post details as I have a chance to test a couple design ideas. I'm hopeing to get to about 250mA to 300mA with the same lumens as a 921 bulb.

The main loss of power in the above circuit is in the 20 ohm resistor and the transistor when the battery voltage is highest (above 12.5V). By using a custom microprocessor controlled "switching" regulator I should be able to recover this wasted power. The design will run cooler too.

Bean
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