Originally Posted by WarMovies
1. Looking into the possibility of running items like a popcorn maker (1000w), juicer (1200w) and the LED tv (?) off of the 12v outlet supplied in my camper rather than fire up the generator.
2. As a bonus learn more about 12v and "power" in general as I want to wire up my LED awning lights to 12v and want to tap into existing source w/o overloading it.
Was doing the light bulb equation to put a visual on fuse capacity.
Okay, let's see if we can make this simpler in the conversions. I'm going to round off stuff to make it easier and not take into account that 12 volt can be really 12.5 volt.....or AC voltage drops requiring more amps, inverter inefficiences, etc.
Let's do this two ways: First let's figure wattage which is volts times amps.
120 volts AC times 10 amps equal 1200 watts....or what your juicer needs to run off of AC/electricity. You would need 10 amps of AC to power this juicer, and on a 30 amp equipped RV, this is a full third of your available amps that you have.
You can do the the math another way and get amps. Let's take watts and divide by voltage (either 120 volt AC or 12 volt DC). This time we will take the known 1200 watts of the juicer but divide it by the 12 volts.....which would be 100 amps DC.
So to run a 1200 watt juicer, you would need to use 100 amps of DC (battery), and would need greater than a 100 amp DC fuse and properly sized wire for this.
EDIT: If you plug the above numbers (120 volt AC and 10 amps) to get 1200 watts in the conversion link, it states you need 110.4 amps DC to run the juicer.
To put it even simpler, let's talk about your converter. Your RV converter is what converts AC power into DC power. Your converter is usually rated for something like 45, 55, or 75 DC amps. Say your converter can supply 75 amps of DC power to provide power for your furnace, fridge, detectors, battery charger, and so forth.
Your 1200 watt juicer that will require 100+ amps of DC, would be using more DC power than everything else combined in your trailer that your converter powers at 75 amps DC........and would also be need to be on it's own circuit and couldn't be run thru the converter at all since it would require more amps than the entire total of the converter is capable of producing..
Does that help any in the understanding of the draws?
If I misquoted or made any errors in my posts, would someone please clarify?